Having approximated the engine’s steam consumption at a given speed and having calculated the consumption of fuel for the boiler I should now be able to calculate the Steam Engine and Boiler Efficiency.
In my previous post on steam and methylated spirit consumption the final calculation looked like this:
The engine design for my traction engine is 12mm bore and 12mm stroke. Volume of working fluid consumed per revolution:
π x 0.62 (bore in cm) x 1.2 (stroke in cm) x 2 (double acting) = 2.7cc / rev
at 300rpm x 2.7cc => 810cc/min
At the end of the stroke the steam will still be under pressure. I’ve assumed the steam will still be at 1.5 atmospheres
810 / 880 x 1.5 = 1.38g water per minute => 0.26g fuel / minute
This feels like a fairly simple walk through of the steam and methylated spirit consumption.
Steam and Methylated Spirit Consumption
Engine Power
With a 12mm bore and 12mm stroke engine running at 300rpm and with steam at 3 atmospheres then the peak force:
3atm at beginning of stroke, 1.5atm at end of stroke, approximately 2.25atm when the crank is at 90° to the piston main axis:
- Bore = 12mm, Area = π x 62= 113mm2
- Force = 225,000 x 113 / 1,000,000 ~ 25N
- Torque = 25 x 0.006 = 0.15Nm
Power = Torque x Speed / 9.5488
Watts = Nm x rpm / 9.5488
Engine power = 0.15 x 300 / 9.5488 ~ 4.7W
A piston and crank create a sinusoidal torque with a double acting piston, this means that my effective average torque is 0.7x this value, so my power out of the engine is approximately, 0.7 x 4.7 ~ 3.3W
Heat Input Power
From the previous calculation we had the following:
810 / 880 x 1.5 = 1.38g water per minute => 0.26g fuel / minute
we have a heating value for the methylated spirits of 29700J/g
0.26 x 29700 = 7722 J/minute = 128.7 J/second = 128.7 Watts
Efficiency
I now have an input power of 128.7 Watts and an engine output power of 3.3 Watts, the Steam Engine and Boiler Efficiency is a ratio of the output and input:
Steam Engine and Boiler Efficiency = Output Power / Input Power
Miniature Traction Engine Efficiency = 3.3 / 128.7 = 0.0256 = 2.56%
So, my calculated efficiency is 2.56% that feels very high for this small system and I expect a lot more losses when I put this into practice.
The LittleLEC 2019 competition that measures the overall efficiency of steam trains recorded results between 0.057% up to 0.428%, an order of magnitude lower efficiency than my simple calculation.
LittleLEC 2019, Reference 2
I need to go back to the steam indicator diagram and take a look at the real losses.
References
- Condensers and Boilers for Steam-Powered Cars, NASA Technical Server
- LitteLEC Model Steam Train Efficiency Competition
